Analisis Diagram Energi Kincir Air
Energi Mekanik di Posisi A
v = 2√15 m/s, h = 0 m
EMA = EPA + EKA
EMA = 0 + 1/2 mvA²
EMA = 0 + 1/2 m(2√15)²
EMA = 0 + 1/2 m(60)
EMA = 30 m Joule
Posisi B
h = 1,5 m
Analisis Diagram Energi Kincir Air
Energi Mekanik di Posisi A
v = 2√15 m/s, h = 0 m
EMA = EPA + EKA
EMA = 0 + 1/2 mvA²
EMA = 0 + 1/2 m(2√15)²
EMA = 0 + 1/2 m(60)
EMA = 30 m Joule
Posisi B
h = 1,5 m
Editor: Fajar Sidik Nur Cahyo
Sumber: guru.kemdikbud.com